![]() ![]() What will produce this? Well, obviously 8V RMS into an 8 ohm load. Generally, an 8W audio amplifier means 8W RMS with a sinewave input such as 1 KHz. I'm afraid you haven't thought this through. A speaker with 8-ohm impedance and a voltage gain of 10 is wanted. The power supply is from 9V to -9V and the input is 0.8Vp 1 kHz. ![]() I need to design an 8W audio amplifier with BJTs. In your case your getting about 7 volts swing, which is a very reasonable number.īut this is not your big problem. So the output can never be greater than about 7.5 volts for a 9-volt supply - and this is an absolute limit. The voltage across a Darlington cannot be less than two diode drops, which would amount to about 1.5 volts. Your first problem is your choice of a Darlington follower for your output stage.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |